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K,
East following with the higher of touching clubs
T
to show an even suit length (low would have shown odd )>
A won the trick.
K was won by West's
A,
East showing even diamond count with the high spot, clearly 4 given the raise
to 2
.
5
(odd encourages, even discourages).
7 was led and in isolation the spade suit from
above was:
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Normally after dummy plays low, East contributes the
T
and eventually nets two spade tricks rather than just one with the
A.
As it was, declarer won the
K, won a
T
ducked by West and then dummy's
A
The declarer's 2nd spade was discarded on dummy's
K
and the third was discarded on dummy's established clubs, West ruffing with
a natural winner.
If South could be counted upon for 6 hearts for the risky 3
bid and West could be counted on for at least 5 diamonds for the rebid of
3
, South would have precisely 1 diamond (
:
13 - west5 - dummy3 - east4 = south1). All the clubs had been accounted for,
South having followed to 3 rounds.
South would then have at most 3 spades to start with, at least one to be discarded
on the
Q.
With no 2nd spade winner possible then, East winning the
A
immediately was a favourite.
As it was, taking the setting trick at Matchpoint scoring mattered not at all!
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